The areas of vertical transverse sections of a forward hold, spaced equidistantly between bulkheads, are as follows: 800, 960, 1100 and 1120sq. m, respectively. The length of the hold is 20m. Find how many tonnes of coal (stowing at 4cu. m per tonne) it will hold.

The areas of vertical transverse sections of a forward hold, spaced equidistantly between bulkheads, are as follows:

800, 960, 1100 and 1120sq. m, respectively.

The length of the hold is 20m. Find how many tonnes of coal (stowing at 4cu. m per tonne) it will hold.

Reference: Ship Stability for Masters & Mates (6^th edition), Exercise – 10.5

 

Solution:

Aw	SM	F(∇)
800	1	800
960	3	2880
1100	3	3300
1120	1	1120
		∑ = 8100

 

Common interval, h = 20/3 = 6.67 m

Volume = 3h/8 * ∑f(∇)

                = 3*6.67/8 * 8100

                = 20250 m³

It will hold = 20250/4 = 5062.5 tons of coal