A ship of 5000 tonnes displacement is 120m long and floats upright on an even keel. When a mass of 40 tonnes, already on board, is shifted 25m forward horizontally, it causes the trim to change by 0.1m. Find the longitudinal metacentric height.

A ship of 5000 tonnes displacement is 120m long and floats upright on an even keel. When a mass of 40 tonnes, already on board, is shifted 25m forward horizontally, it causes the trim to change by 0.1m. Find the longitudinal metacentric height.

Reference: Ship Stability for Masters & Mates (6^th edition), Exercise – 16.25

 

Solution:

GG₁ = 40*25/5000 = 0.2 m

GM_L /GG₁ = L/t

=> GM_L/0.2 = 120/0.1

=> GM_L = 240 m