A ship of 18 000 tonne displacement has KB 5.25 m, KG 9.24 m and second moment of area about the centreline of 82 × 103 m4. Using the wall-sided formula calculate the righting levers at intervals of 5° heel up to 20° and sketch the stability curve up to this angle.
A ship of 18 000 tonne displacement has KB 5.25 m, KG 9.24 m and second moment of area about the centreline of 82 × 103 m4. Using the wall-sided formula calculate the righting levers at intervals of 5° heel up to 20° and sketch the stability curve up to this angle.
Reference:
REED'S NAVAL ARCHITECTURE FOR MARINE ENGINEERS (4th edition),
Exercise – 5.16
Solution:
GZ = sinθ
(GM + 0.5BM*tan2θ)
BM = I/∇
= 82*103
* 1.025/18000
= 4.67 m
GM = KB + BM – KG
= 5.25 + 4.67 –
9.24
= 0.68 m
|
θ |
0.5BM*tan2θ |
GM + 0.5BM*tan2θ |
Sinθ |
GZ |
|
0 |
0 |
0.68 |
0 |
0 |
|
50 |
0.018 |
0.698 |
0.087 |
0.061 |
|
100 |
0.073 |
0.753 |
0.177 |
0.131 |
|
150 |
0.168 |
0.848 |
0.258 |
0.219 |
|
200 |
0.309 |
0.989 |
0.342 |
0.338 |
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